Yadda za a nemo wurin zama na rectangle a gefensa, ta wurin yanki da gefe ɗaya, ta hanyar kusurwa tsakanin ta gefen ta gefen gefen gefen gefe

Sau da yawa a rayuwa, mutane suna buƙatar samun wurin zama na rectangle. Wannan matsala ta auku, alal misali, a lokuta inda ya wajaba don lissafin tsawon shinge ko adadin takalma mai dacewa don ginin ganuwar cikin ɗaki. Gaskiya ne, a cikin akwati na ƙarshe, wannan wuri shine kawai hanyar haɗin kai a cikin mafita na matsala mai amfani. Amma, duk da haka, a wannan yanayin, mutane da bukatar sanin yadda za a sami kewaye da wani murabba'i mai dari.

Don fara, ina so in ayyana abin da yake kewaye. Kewaye, a gaskiya, iyakar wani musamman na lissafi siffar ko jimlar tsawon gẽfunanta. Yanzu bari mu bayyana ma'anar ma'anar madaidaiciya. Dole ne a yi la'akari da kuskuren kusurwa tare da kusurwoyi na kusurwoyi. A gaskiya, ainihin fassarar alama shine daidai kusurwarsa ta kusurwa, wanda ya kamata ya kasance cikin wannan nau'i na siffar siffa huɗu.

Saboda haka, don samun cikakken tsawon iyakokin rectangle, ya zama dole don ƙara tsawon tsawon kowane sashi. Kamar yadda muka riga muka bayyana, sassan da ke cikin rectangle daidai ne, sabili da haka, don fahimtar hankali, ya kamata a fahimci cewa wurin zama na rectangle daidai yake da sau biyu na adadin bangarorin biyu.

Don tsabta, za mu yi daidai da daidai a cikin rectangle tare da haruffan "a" da "b" na haruffan Latin, daidai da haka. Ta haka ne, ya juya cewa P (wurin na rectangle) = a + b + a + b. Za'a iya canza wannan daidaitattun kamar haka: P = 2X (a + b).

Duk da haka, a rayuwa akwai sau da yawa yanayi inda tsawon tsinkaya guda ɗaya da sauran sassa a cikin rectangle da aka sani, ko a waje. Bari muyi la'akari da wasu bambance-bambancen.

Alal misali, muna buƙatar lissafin abin da kewaye da rectangle yake daidai da, idan dai ba a san tsawon tsawon ɗayan a cikin rectangle ba, amma an san yankin. Dole ne, ta yin amfani da mahimmanci don ƙididdige yankin na rectangle, wanda yake daidai da samfurin da ke gefensa, don lissafin tsawon ta gefe na biyu. Wannan yana da sauƙin yi ta rarraba yankin da aka sani a cikin sanannun sanannun. Sanin ɓangarorin biyu na rectangle, zaka iya lissafin wurin da ya dace.

Wannan zaɓin ya dace don ƙididdige yawan adadin kayan da za a yi maka shinge na shinge, lokacin da aka ƙayyade yankin a cikin takardun. Ya zama wajibi ne kawai don auna ɗaya daga cikin bangarori na mãkirci. Amma wani lokaci kana buƙatar sanin yadda za a samu wurin zama na rectangle, idan an san ɗaya daga cikin ɓangarori na rectangle da diagonal.

A dabi'a, mataki na farko a cikin lissafi shi ne ya sami tsawon gefe na biyu na rectangle. Ana iya ƙidaya shi ta hanyar ilimin Pythagorean, wanda ya nuna cewa hypotenuse na alƙalan hagu mai kusurwa, ƙwallon ƙafa, ya hada da adadin murabba'ai na bangarorin biyu. Saboda haka, don lissafta, muna buƙatar gina tsawon zangon sakonni da tsawon tsinkayen da aka sani a fili, sa'annan mu sami bambanci tsakanin su, kuma tun daga wannan bambanci muna buƙatar cire tushen tushe.

A sakamakon square tushen da zai zama ba a sani ba gefe tsawon. Kuma tun lokacin da za ka iya samun wurin zama na madaidaiciya ta ƙara ƙididdigar da aka sani da kuma jujjuya su, to, kowa zai iya magance wannan tsari.

Ayyukan ilmin lissafi sunyi la'akari da tambayar yadda za a samu wurin zama na madaidaiciya ta hanyar kwance ta tsakiya da kuma kusurwa mai kusurwa wanda aka kafa ta hanyar diagonal da ɗaya daga cikin ɓangarori na madaidaiciya. A nan muna da misali mai kyau na yin amfani da darajar sine a lissafi. Daga shirin makaranta, kowa ya san cewa sine na kusurwa na tauraron rectangular daidai yake da rabo daga kafa na kusa da hypotenuse. Daga wannan ya biyo da ma'anar: zunubi X = kama: hypotenuse (diagonals na rectangle).

Za a iya gane sinus da sauƙin ganewa ta wurin Bradys, abin da aka sani na diagonal - hypotenuse an sauya shi a cikin tsari, kuma ɗaya daga cikin ɓangarorin na rectangle ana sauƙin lissafi. Yanzu mataki na gaba shi ne neman sashe na biyu na rectangle. A nan, bambancin da aka dauka a sama ya zo cikin karfi ta amfani da ka'idar Pythagoras. Mun sanya siginar da aka sani da kuma cirewa daga samfurin da aka samo asali na gefen da aka samo. Daga amsar, muna cire tushen tushen. Daga sanannun ɓangarorin da aka sani yanzu, za ka iya lissafin wurin ta ƙara ƙayyadadinsu kuma ka ninka su.

A halin da ake ciki, wannan ba cikakke ne daga cikin misalan ba, a gaskiya akwai wasu da yawa, amma wadanda aka bayyana a sama an fi fuskantar su da yawa.

Sabili da haka, zamu iya cewa ba tare da sanin tsawon tsayi guda biyu ba daidai ba, yanayin kewaye da rectangle bai kusan yiwuwa ba. Duk da haka, yin amfani da ilimin lissafin ilimin lissafi da kuma axioms, wanda zai iya lissafta wurin zama na rectangle kowane lokaci, yana ƙara dukkan bangarori.